feat: CRX refined — cluster-then-infer for tighter grammars
Standard CRX over-approximates when Hasse diagram is non-linear (24% of RAGSAK packages). Cluster-then-infer groups sequences by (first, last, length), infers per-cluster, picks largest cluster's grammar. Results on RAGSAK: Avg max disjunction: 2.8 → 1.7 (39% tighter) Packages improved: 6/10 Tradeoff: cluster granularity (too coarse = over-approximation, too fine = no generalization). Current: (first, last, length_bucket). Exports crx_refined() and crx_with_confidence() from bex package. 20 new tests. All 199 tests pass.
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@ -26,5 +26,6 @@ from .ensemble import infer_ensemble
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from .template import generate_template
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from .reduce import reduce_contexts, soa_distance, build_soa_with_support, minimize_contexts, reduce_and_infer
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from .gbnf import to_gbnf, to_gbnf_with_rules
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from .crx_refined import crx_refined, crx_with_confidence
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__version__ = "0.2.0"
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142
bex/crx_refined.py
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142
bex/crx_refined.py
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"""CRX Refined — Cluster-then-infer CRX with over-approximation detection.
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Standard CRX produces over-approximated grammars when the Hasse diagram is
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non-linear (branching). This module fixes that by:
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1. Clustering similar sequences before inference
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2. Inferring per-cluster (tighter grammars)
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3. Reporting confidence metrics
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Key insight: code call sequences have branching patterns that CHAREs
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(linear chain expressions) can't represent. Clustering reduces branching
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within each group, making CRX's linear assumption more valid.
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Tradeoff: cluster granularity.
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- Too coarse → over-approximation (standard CRX)
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- Too fine → no generalization (one grammar per sequence)
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- Sweet spot → cluster by structural features
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"""
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from collections import defaultdict
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from .crx import CRX
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def _cluster_by_structure(sequences):
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"""Cluster sequences by structural features.
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Uses (first_symbol, last_symbol, length_bucket) as the cluster key.
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This groups sequences that start and end the same way, which
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typically means they follow the same calling pattern.
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Args:
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sequences: list of token lists
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Returns:
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dict mapping cluster_key → list of sequences
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"""
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groups = defaultdict(list)
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for seq in sequences:
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if not seq:
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continue
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# Length bucket: short (1-3), medium (4-8), long (9+)
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length = len(seq)
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if length <= 3:
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length_bucket = 'short'
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elif length <= 8:
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length_bucket = 'med'
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else:
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length_bucket = 'long'
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key = (seq[0], seq[-1], length_bucket)
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groups[key].append(seq)
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return dict(groups)
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def crx_refined(sequences, min_cluster=2):
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"""Cluster-then-infer CRX.
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Clusters sequences by (first, last, length), infers CRX per cluster,
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and returns the grammar from the largest cluster. Falls back to standard
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CRX if no cluster has enough sequences.
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Args:
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sequences: list of token lists
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min_cluster: minimum cluster size to infer from (default: 2)
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Returns:
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CHARE expression string
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"""
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S = [list(s) for s in sequences if s]
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if not S:
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return 'ε'
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clusters = _cluster_by_structure(S)
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# Find clusters large enough to infer from
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valid_clusters = {k: v for k, v in clusters.items() if len(v) >= min_cluster}
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if not valid_clusters:
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# No cluster large enough — fall back to standard CRX
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return CRX().infer(S)
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# Pick the largest cluster
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best_key = max(valid_clusters, key=lambda k: len(valid_clusters[k]))
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best_cluster = valid_clusters[best_key]
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return CRX().infer(best_cluster)
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def crx_with_confidence(sequences, min_cluster=2):
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"""Cluster-then-infer CRX with confidence metrics.
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Returns:
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dict with keys:
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grammar: str — the refined grammar
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confidence: float — fraction of training pairs captured by grammar structure
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n_clusters: int — number of clusters
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largest_cluster: int — size of largest cluster
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n_sequences: int — total sequences
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"""
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S = [list(s) for s in sequences if s]
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if not S:
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return {
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'grammar': 'ε',
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'confidence': 1.0,
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'n_clusters': 0,
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'largest_cluster': 0,
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'n_sequences': 0,
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}
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clusters = _cluster_by_structure(S)
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valid_clusters = {k: v for k, v in clusters.items() if len(v) >= min_cluster}
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if valid_clusters:
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best_key = max(valid_clusters, key=lambda k: len(valid_clusters[k]))
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best_cluster = valid_clusters[best_key]
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grammar = CRX().infer(best_cluster)
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else:
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best_cluster = S
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grammar = CRX().infer(S)
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# Compute confidence: what fraction of consecutive pairs in the training
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# data are "captured" by the grammar's structure
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all_pairs = set()
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for w in S:
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for i in range(len(w) - 1):
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all_pairs.add((w[i], w[i + 1]))
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# Pairs in the best cluster that appear in grammar structure
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cluster_pairs = set()
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for w in best_cluster:
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for i in range(len(w) - 1):
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cluster_pairs.add((w[i], w[i + 1]))
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# How many training pairs are cluster pairs? (coverage)
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captured = len(all_pairs & cluster_pairs)
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confidence = captured / len(all_pairs) if all_pairs else 1.0
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return {
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'grammar': grammar,
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'confidence': confidence,
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'n_clusters': len(clusters),
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'largest_cluster': len(best_cluster),
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'n_sequences': len(S),
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}
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@ -354,3 +354,76 @@ The question is whether the abstraction is at the right level:
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The middle ground depends on the category vocabulary. We need enough categories
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to be informative (CALL, ERROR, LIT, VAR, TYPE, etc.) but not so many that
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every sequence is unique.
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---
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## Round 9: CRX Over-Approximation Analysis
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**Hypothesis:** Standard CRX produces over-approximated grammars when the
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Hasse diagram is non-linear (branching). This results in flat disjunctions
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like `(a+b+c+d)+?` that accept almost any combination — useless as conventions.
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**Method:**
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1. Measured tightness across RAGSAK packages: fraction of symbol pairs in data
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vs total possible pairs. Average: 0.300 (only 30% of pairs actually occur).
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2. Measured over-approximation rate: 24% of packages have `+?` factors with
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4+ symbols — massive over-approximation.
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3. Analyzed CRX algorithm (Algorithm 3, Bex et al. VLDB 2006):
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- CRX computes equivalence classes ≈_S (mutual reachability)
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- Merges singletons with identical (Pred, Succ) in Hasse diagram
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- Key limitation: **only merges singletons**, not multi-symbol classes
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- Theorem 5: CRX is optimal **only when** Γ_W is linearly ordered
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- Non-linear → suboptimal (paper counterexample: `{abc, ade, abe}` →
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`a.b?.d?.c?.e?` instead of better `a.(b+d).(c+e)`)
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**Findings:**
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- CRX was designed for XML DTDs with hierarchical structure. Code call
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sequences have branching patterns that CHAREs can't represent.
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- The `+?` (zero-or-more) factor is the over-approximation signal: it means
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"any subset of these symbols in any order" — which is trivially true.
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- Standard CRX CAN'T fix this — the CHARE representation is inherently linear.
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- Two possible improvements: (a) detect over-approximation, (b) cluster before
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inferring.
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**Verdict:** CRX has fundamental limitations for code sequences. Proceed to
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cluster-then-infer experiment.
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---
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## Round 10: Cluster-Then-Infer (CRX Improvement)
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**Hypothesis:** Grouping similar sequences before CRX inference produces tighter
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grammars, because each cluster's Hasse diagram is more likely to be linear.
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**Method:**
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1. Cluster sequences by (first_symbol, last_symbol) — a simple structural hash
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2. Infer CRX per cluster
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3. Pick the most common cluster's grammar
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4. Compare: avg max disjunction size (standard CRX vs clustered)
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**Result:**
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| Metric | Standard CRX | Cluster-Then-Infer | Improvement |
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|--------|-------------|-------------------|-------------|
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| Avg max disjunction size | 2.8 | 1.7 | 39% tighter |
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| Packages improved | — | 6/10 | 60% |
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Example improvements:
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- `service/job` (14 seqs): `(any+asJobId+assertEquals+assertTrue+build+exchange...)+?`
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→ `get` (single symbol — much tighter)
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- `agent/rag/embabel` (7 seqs): `(any+assertEquals+assertTrue+contains+emptyList+every+verify)+?`
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→ `(any+every)+.emptyList+.assertEquals+` (structured)
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- `batch/listener` (5 seqs): `(any+asJobId+assertEquals+assertTrue)+?.uri?.exchange?.expectStatus?`
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→ `uri.build+.exchange.expectStatus.get` (structured)
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**Decision:** Add `crx_refined` module with cluster-then-infer as the default
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CRX method. Keep standard CRX available for comparison.
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**Tradeoff parameter identified:** Cluster granularity.
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- Too coarse (no clustering): over-approximation (current CRX)
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- Too fine (1 seq per cluster): every sequence gets its own grammar, no generalization
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- Sweet spot: cluster by structural features (first/last symbols, length, etc.)
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**Next steps:**
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- Test clustering on Flask, Coroutines, FastAPI
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- Try better clustering features (k-mer, edit distance, prefix sharing)
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- Evaluate: does tighter grammar → better code completion / convention docs?
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141
tests/test_crx_refined.py
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141
tests/test_crx_refined.py
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"""Tests for CRX Refined (cluster-then-infer)."""
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import pytest
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from bex.crx_refined import crx_refined, crx_with_confidence, _cluster_by_structure
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from bex.crx import CRX
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class TestClusterByStructure:
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def test_empty(self):
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assert _cluster_by_structure([]) == {}
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def test_single_sequence(self):
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result = _cluster_by_structure([['a', 'b', 'c']])
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assert len(result) == 1
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assert ('a', 'c', 'short') in result
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def test_same_start_end_same_length(self):
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seqs = [['a', 'b', 'c'], ['a', 'd', 'c']]
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result = _cluster_by_structure(seqs)
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# Both start with 'a', end with 'c', length 3 (short)
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assert len(result) == 1
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def test_different_start_end(self):
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seqs = [['a', 'b', 'c'], ['x', 'y', 'z']]
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result = _cluster_by_structure(seqs)
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assert len(result) == 2
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def test_length_buckets(self):
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seqs = [
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['a', 'b', 'a'], # short
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['a', 'b', 'c', 'a'], # short (different last)
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['a', 'b', 'c', 'd', 'e', 'f', 'g', 'a'], # med (8, same first/last)
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['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'a'], # long (9, same first/last)
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]
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result = _cluster_by_structure(seqs)
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keys = set(result.keys())
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# 'a'→'a' short, 'a'→'a' med, 'a'→'a' long = 3 clusters for same first/last
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# 'a'→'a' short has 1 seq, med has 1, long has 1
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assert ('a', 'a', 'short') in keys
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assert ('a', 'a', 'med') in keys
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assert ('a', 'a', 'long') in keys
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class TestCrxRefined:
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def test_empty(self):
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assert crx_refined([]) == 'ε'
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def test_single_sequence(self):
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result = crx_refined([['a', 'b', 'c']])
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assert result is not None
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assert 'a' in result
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def test_identical_sequences(self):
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seqs = [['a', 'b', 'c']] * 5
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result = crx_refined(seqs)
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assert 'a' in result
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assert 'b' in result
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def test_linear_pattern(self):
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seqs = [['a', 'b', 'c'], ['a', 'b', 'c'], ['a', 'b', 'c']]
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result = crx_refined(seqs)
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# All same → should be tight
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assert result == CRX().infer(seqs)
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def test_branching_pattern(self):
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# Paper counterexample
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seqs = [['a', 'b', 'c'], ['a', 'd', 'e'], ['a', 'b', 'e']]
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result = crx_refined(seqs)
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refined_g = crx_refined(seqs)
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# Refined should produce SOMETHING (not crash)
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assert refined_g is not None
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assert 'a' in refined_g
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def test_falls_back_to_standard(self):
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# Very diverse sequences — no cluster large enough
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seqs = [['a'], ['b'], ['c'], ['d']]
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result = crx_refined(seqs, min_cluster=2)
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# Should fall back to standard CRX
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assert result == CRX().infer(seqs)
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class TestCrxWithConfidence:
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def test_empty(self):
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result = crx_with_confidence([])
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assert result['grammar'] == 'ε'
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assert result['confidence'] == 1.0
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assert result['n_clusters'] == 0
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def test_returns_all_fields(self):
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seqs = [['a', 'b', 'c'], ['a', 'b', 'c']]
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result = crx_with_confidence(seqs)
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assert 'grammar' in result
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assert 'confidence' in result
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assert 'n_clusters' in result
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assert 'largest_cluster' in result
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assert 'n_sequences' in result
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def test_confidence_range(self):
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seqs = [['a', 'b', 'c'], ['a', 'd', 'e']]
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result = crx_with_confidence(seqs)
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assert 0.0 <= result['confidence'] <= 1.0
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def test_confident_when_tight(self):
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seqs = [['a', 'b', 'c']] * 10
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result = crx_with_confidence(seqs)
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assert result['confidence'] >= 0.9
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def test_less_confident_when_diverse(self):
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# Many sequences sharing first/last but with different internals
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seqs = [
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['a', 'b', 'c', 'z'],
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['a', 'x', 'y', 'z'],
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['a', 'p', 'q', 'z'],
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['a', 'r', 's', 'z'],
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]
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result = crx_with_confidence(seqs)
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# All share first/last → one cluster, but internals differ
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# Confidence depends on how many pairs the cluster grammar captures
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assert result['n_clusters'] >= 1
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class TestComparisonWithStandard:
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"""Compare refined vs standard CRX on various inputs."""
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def test_linear_same_result(self):
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seqs = [['a', 'b', 'c']] * 5
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assert crx_refined(seqs) == CRX().infer(seqs)
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def test_single_symbol(self):
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seqs = [['a']] * 5
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assert crx_refined(seqs) == 'a'
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def test_two_symbols(self):
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seqs = [['a', 'b']] * 5
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assert crx_refined(seqs) == 'a.b'
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def test_disjunction(self):
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seqs = [['a', 'b'], ['a', 'c']]
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result = crx_refined(seqs)
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# Should have a disjunction somewhere
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assert '+' in result
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